Curriculum Python if, elif and else for KidsOrder and overlap

Why elif Order Changes the Answer in Python

Why elif's ORDER can make a branch impossible to reach — and when separate ifs are the right call instead.

Lesson 5 of 5PROAges 10+

Order and overlap

You know elif stops at the first match. Here's a trap that causes: writing the conditions in the wrong ORDER.

score = 95. This chain checks the LOOSE condition first — watch what happens to the branch below it.

score = 95
if score > 50:
    print("Good")
elif score > 80:
    print("Excellent")

Output

Good

Excellent never prints — and it NEVER CAN, for any score. Every value bigger than 80 is also bigger than 50, so the first check always wins first.

Fix it by putting the NARROWEST, most specific condition first. Same two conditions, opposite order.

score = 95
if score > 80:
    print("Excellent")
elif score > 50:
    print("Good")

Output

Excellent

Same rule, now with score = 60 — it doesn't satisfy > 80, so it falls through to check > 50 instead.

elif only checks each condition if every one above it was False — so the order you write them in changes what's actually reachable.

score = 60
if score > 80:
    print("Excellent")
elif score > 50:
    print("Good")

Output

Good

Now a completely different question: does everything with more than one condition NEED elif? No.

burns_survived = 3, rooms_found = 5 — two UNRELATED facts. Both badges should be earned. elif here would be the bug.

burns_survived = 3
rooms_found = 5
if burns_survived >= 3:
    print("Fireproof")
elif rooms_found >= 5:
    print("Explorer")

Output

Fireproof

Explorer never printed — elif skipped it because Fireproof's condition already matched. But these facts don't compete, so that's wrong.

Two SEPARATE ifs fix it — each one checked on its own, so both badges can be earned in the same run.

burns_survived = 3
rooms_found = 5
if burns_survived >= 3:
    print("Fireproof")
if rooms_found >= 5:
    print("Explorer")

Output

Fireproof
Explorer

The rule: elif for tiers of ONE thing, where only one should ever win. Separate ifs for independent facts, where more than one can be true.

Check your understanding

score = 95. What does this print? if score > 50: print("Good") elif score > 80: print("Excellent")

score = 95
if score > 50:
    print("Good")
elif score > 80:
    print("Excellent")

Good
Excellent — 95 is a better match for that condition
Both Good and Excellent

Why: Good — and Excellent can NEVER print with this ordering, for ANY score. Every number that satisfies score > 80 also satisfies score > 50, and score > 50 is checked first. Writing the narrower, more specific condition FIRST is what makes a branch reachable at all.

burns_survived = 3, rooms_found = 5 — the adventurer earned BOTH badges. Which code correctly awards both?

if burns_survived >= 3:
    print("Fireproof")
??? rooms_found >= 5:
    print("Explorer")

Two separate if statements
if / elif — elif is always the safer choice once there's more than one condition

Why: Two separate ifs — because Fireproof and Explorer are independent facts, not competing tiers. elif would silently drop Explorer the moment Fireproof matched, the same order-sensitivity trap as an unreachable elif branch, just from the opposite direction: chaining things that were never supposed to compete.

What you'll practice

points = 95. Give exactly one reward tier: 90 or more is Platinum, 70 or more (but under 90) is Gold, anything else is Silver. Write the chain with the NARROWEST, highest condition FIRST — if you check the loose condition first, the tight one can never be reached.

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Order and overlap

Check your understanding

What you'll practice

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